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An energy efficient household uses 3.2 kWh electrical energy per day. To utilise wind-power they need to be able tostore energy which will then be used to drive an electric generator. They are planning to use water pumped to a hightank for energy storage.
a) How much water should they have stored for 2 days supply, if the water is stored at height of 15 m above theturbine, in order to store the equivalent to 2 days electrical energy in gravitational potential energy form?
first, be sure you recognize that kWh is a unit of energy; W stands for Watt, and 1 W is 1 Joule/sec; so multiplying Watts (energy/sec) times a unit of time (secs) gives you (energy/sec)x(sec) =energy
now we convert 6.2 kWh into the MKS unit of energy, Joules:so in two days, the house uses 6.2 kWh of energy; this is equivalent to:
6.2 kWh = 6200 W h (k=kilo=1000)6200 W h = 6200 W (3600 sec/hr)(hr) = 2.23×10^7 J
the grav potential energy of a mass m is given by:
PE = m g h where m is the mass, g is the accel due to grav (9.8 m/s/s) and h is the height above the earth, so here, the PE is:
PE = 9.8 m/s/s (15 m) h = 147 m J
and this amount of PE must equal 2.23×10^7 J
m=2.23×10^7J/1.47×10^2m^2/s^2 = 1.52×10^7 kg of water
and your answer is 1.52×10^7 kg water
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Hope that helps.
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That sounds particularly charming. I wonder if they allow you to bring your own beef? LOL!
A tornado won’t topple it.
Something with a higher gravitational potential energy than you or I
If it is field corn then you should leave it in a cool dry place out of the sun with airflow. To ensure that it dries ok you should make the pile as spread out as possible.